[LeetCode] #7 Reverse Integer

it2022-05-05  130

Reverse digits of an integer.

Example1: x = 123, return 321Example2: x = -123, return -321

题目很简单,先判断数字的正负,再按位倒置数字就可以了。不过要考虑int的上限。时间:16ms

代码如下:

class Solution { public: int reverse(int x) { bool sign = x > 0 ? false : true; int temp = x > 0 ? x : 0-x; long long y = 0; while (temp){ y = y * 10 + temp % 10; temp = temp / 10; } if (y > 2147483647 || (0- y > 2147483648)) return 0; if (sign == true) y = 0 - y; return y; } };

 

转载于:https://www.cnblogs.com/Scorpio989/p/4412305.html


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