oracle 实现日历

it2022-05-05  82

SELECT  CASE WHEN (new_yweek = MIN(new_yweek)OVER(PARTITION BY mon ORDER BY new_yweek)) THEN mon_name ELSE NULL END AS month, new_yweek AS yweek,  ROW_NUMBER() over(PARTITION BY mon ORDER BY new_yweek) AS mweek,  SUM(DECODE(wday, '1', mday, NULL)) AS sun,  SUM(DECODE(wday, '2', mday, NULL)) AS mon,  SUM(DECODE(wday, '3', mday, NULL)) AS tue,  SUM(DECODE(wday, '4', mday, NULL)) AS wed,  SUM(DECODE(wday, '5', mday, NULL)) AS thu,  SUM(DECODE(wday, '6', mday, NULL)) AS fri,  SUM(DECODE(wday, '7', mday, NULL)) AS sat FROM  (SELECT   dayofyear AS everyday,   TO_CHAR(dayofyear, 'mm') AS mon,  TO_CHAR(dayofyear, 'Month') AS mon_name,   TO_CHAR(dayofyear, 'w') AS mweek,   TO_CHAR(dayofyear, 'ww') AS yweek,   CASE WHEN (TO_CHAR(TO_DATE('2012'  || '0101', 'yyyymmdd'), 'd') > '1') AND (TO_CHAR(dayofyear, 'd') < TO_CHAR(TO_DATE('2012' || '0101', 'yyyymmdd'), 'd')) THEN TO_CHAR(TO_CHAR(dayofyear, 'ww') + 1, 'fm00') ELSE TO_CHAR(dayofyear, 'ww') END AS new_yweek,   TO_CHAR(dayofyear, 'd') AS wday,   TO_CHAR(dayofyear, 'dd') AS mday  FROM   (SELECT    TO_DATE('2012' || '0101', 'yyyymmdd') + LEVEL - 1 AS dayofyear   FROM DUAL    CONNECT BY LEVEL <= TO_CHAR(TO_DATE('2012' || '1231', 'yyyymmdd'),'ddd'))) GROUP BY mon, mon_name, new_yweek

原文:http://busyfan.itpub.net/post/31671/288489

我把日期改了一下

 

转载于:https://www.cnblogs.com/baiyixianzi/archive/2012/08/29/plsql08.html

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