from django.utils.module_loading
import import_string
from django.conf
import settings
# for django 1.0
# from django.urls import RegexURLResolver, RegexURLPattern
# for django 2.0
from django.urls.resolvers
import URLResolver, URLPattern
def recursion_urls(pre_namespace, pre_url, urlpatterns, url_ordered_dict):
"""
递归的去获取URL
:param per_namespace: namespace前缀，以后用户拼接name
:param per_url: url前缀，以后用于拼接url
:param urlpatterns: 路由关系列表
:param url_ordered_dict: 用于保存递归中获取的所有路由
:return:
"""
for item
in urlpatterns:
if isinstance(item, URLPattern):
# 非路由分发
if not item.name:
continue
if pre_namespace:
name =
'%s:%s' %
(pre_namespace, item.name)
else:
name =
item.name
url = pre_url +
str(item.pattern)
url_ordered_dict[name] = {
'name': name,
'url': url.replace(
'^',
'').replace(
'$',
'')}
elif isinstance(item, URLResolver):
if pre_namespace:
if item.namespace:
namespace =
'%s:%s' %
(pre_namespace, item.namespace)
else:
namespace =
pre_namespace
else:
if item.namespace:
namespace =
item.namespace
else:
namespace =
None
recursion_urls(namespace, pre_url +
str(item.pattern), item.url_patterns, url_ordered_dict)
def get_all_url_dict():
"""
获取项目中所有的URL
:return:
"""
url_ordered_dict =
OrderedDict()
md =
import_string(settings.ROOT_URLCONF)
recursion_urls(None, '/', md.urlpatterns, url_ordered_dict)
# 递归去获取所有的路由
return url_ordered_dict
转载于:https://www.cnblogs.com/xiangxiaolin/p/11185081.html
