ajax的post请求方式

it2022-05-08  9

<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%><%String path = request.getContextPath();String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/";%>

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"><html> <head> <base href="<%=basePath%>"> <meta http-equiv="Content-Type" content="text/html;charset=UTF-8"> <title>This is my JSP page</title> <meta http-equiv="pragma" content="no-cache"> <meta http-equiv="cache-control" content="no-cache"> <meta http-equiv="expires" content="0"> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="This is my page"> <!-- <link rel="stylesheet" type="text/css" href="styles.css"> --> <style type="text/css"> div{ border: 1px solid red; width: 400px; height: 300px; } </style> </head> <body> <input type="button" value="Ajax" οnclick="testAjax()"> <div id="msg"></div> </body> <script type="text/javascript"> function testAjax(){ //document.getElementById("msg").innerHTML = "加载中..."; //id; var request; //创建 request对象 if(window.XMLHttpRequest){ //兼容性 request = new XMLHttpRequest(); }else if(window.ActiveXObject){ //针对IE request = new ActiveXObject("Msxml2.XMLHTTP"); } //写监听 去check request的状态 request.onreadystatechange = function(){ // //console.log(request.readyState); if(request.readyState == 4){ //得到 后台写出的数据 //当加载成功以后 if(request.status == 200){ //得到的的是一个json字符串 var data = request.responseText; //将json字符串转换为json对象 eval("data = "+data); document.getElementById("msg").innerHTML = data.password; }else if(request.status == 404){ document.getElementById("msg").innerHTML = "资源没有找到"; }else if(request.status == 500){ document.getElementById("msg").innerHTML = "服务器错误"; } }else{ document.getElementById("msg").innerHTML = "<img src=\"images/loading.gif\" />"; } }; //打开请求 //如果在 地址栏上面 的参数 的值中包含 # 应该将其编码 然后在传递 request.open("post", "ajax/ajaxController?name="+encodeURIComponent("lisi#123")+"&d="+new Date().getTime()); //encodeURIComponent(uriComponent) //发送数据 //如果没有数据 则写null 不然 其他浏览器可能会报错 //如果在 send方法中传参数 则一定要设置 请求头信息中的 Content-Type 为 application/x-www-form-urlencoded request.setRequestHeader("Content-Type", "application/x-www-form-urlencoded"); //如果是 post传参 他和 参数的组织方式 是有关系的 request.send("username=lisi#123&age=123"); } </script></html>

转载于:https://www.cnblogs.com/hwgok/p/5845068.html


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