//题目类型：水题（数论）//解题思路：看清题意，直接推导公式即可 #include <iostream>#include <stdio.h>//#include <conio.h>#include <math.h>using namespace std;double temper,humidex,dew;void solvedew(){ dew = 1/(1/273.16-log((humidex-temper+5.555)/(0.5555*6.11))/5417.7530)-273.16;}void solvetemper(){ temper = humidex-(0.5555)*(6.11*exp(5417.7530*((1/273.16) - (1/(dew+273.16)))) - 10.0);}void solvehumidex(){ humidex = temper + (0.5555)*(6.11*exp(5417.7530*((1/273.16) - (1/(dew+273.16)))) - 10.0); }int main(){ //freopen("1.txt","r",stdin); bool botemper,bohumidex,bodew; char ch[5]; while(1) { botemper = false; bohumidex = false; bodew = false; scanf("%s",ch); //尽量采用字符串读字符 if(ch[0]=='E') break; else if(ch[0]=='T') { scanf("%lf",&temper); //G++中双精度浮点数使用scanf读取时依然采用%lf botemper = true; } else if(ch[0]=='D') { scanf("%lf",&dew); bodew = true; } else if(ch[0]=='H') { scanf("%lf",&humidex); bohumidex = true; } scanf("%s",ch); if(ch[0]=='T') { scanf("%lf",&temper); botemper = true; } else if(ch[0]=='D') { scanf("%lf",&dew); bodew = true; } else if(ch[0]=='H') { scanf("%lf",&humidex); bohumidex = true; } if(bodew && botemper) solvehumidex(); else if(bodew && bohumidex) solvetemper(); else if(botemper && bohumidex) solvedew(); //printf("T %.1lf D %.1lf H %.1lf\n",temper,dew,humidex); printf("T %.1f D %.1f H %.1f\n",temper,dew,humidex); //特别注意G++中不支持%lf } //getch(); return 0;}
转载于:https://www.cnblogs.com/north_dragon/archive/2010/09/29/1838304.html
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