//组合数打表模板,适用于N<=3000
//c[i][j]表示从i个中选j个的选法。
long long C[N][N];
void get_C(
int maxn)
{
C[0][
0] =
1;
for(
int i=
1;i<=maxn;i++
)
{
C[i][0] =
1;
for(
int j=
1;j<=i;j++
)
C[i][j] = C[i-
1][j]+C[i-
1][j-
1];
//C[i][j] = (C[i-1][j]+C[i-1][j-1])%MOD;
}
}
转载于:https://www.cnblogs.com/zsben991126/p/10548174.html
转载请注明原文地址: https://win8.8miu.com/read-14797.html