A robot is located at the top-left corner of a m x n grid (marked 'Start' in the diagram below).
The robot can only move either down or right at any point in time. The robot is trying to reach the bottom-right corner of the grid (marked 'Finish' in the diagram below).
How many possible unique paths are there?
Above is a 7 x 3 grid. How many possible unique paths are there?
Note: m and n will be at most 100.
Example 1:
Input: m = 3, n = 2 Output: 3 Explanation: From the top-left corner, there are a total of 3 ways to reach the bottom-right corner: 1. Right -> Right -> Down 2. Right -> Down -> Right 3. Down -> Right -> Right典型的数据结构套路题，状态转移方程：f[i][j]=f[i][j-1]+f[i-1][j];ac代码：#include<iostream>#include<vector>using namespace std;int uniquepaths(int m,int n){ vector<vector<int> > f(m, vector<int>(n)); //vector开辟二维数组 for(int i=0;i<m;i++) f[i][0]=1; for(int j=0;j<n;j++) f[0][j]=1; for(int i=1;i<m;i++) for(int j=1;j<n;j++) { f[i][j]=f[i-1][j]+f[i][j-1]; } return f[m-1][n-1];}int main(){ int m,n; while(cin>>m>>n) { cout<<uniquepaths(m,n)<<endl; }}
转载于:https://www.cnblogs.com/flyljz/p/10978963.html
