1.使用while循环输入 1 2 3 4 5 6     8 9 10

count=0 while count<10: count+=1 if count==7: continue print(count)

2.求1-100所有数的和

sum=0 for i in range(101): sum+=i print(sum)

3.输出1-100内的所有奇数

li=[] for i in range(1,101): if i%2==1: li.append(i) print(li)

4.输出1-100内的所有偶数

li=[] for i in range(1,101): if i%2==0: li.append(i) print(li)

5.求1-2+3-4+5 ... 99的所有数的和

sum=0 for i in range(100): if i %2 ==0: sum-=i if i%2==1: sum+=i print(sum) #方法2 sum=0 j=1 for i in range(1,100): sum+=i*j j=-j print(sum)

6.用户登录，三次机会重试

count=0 while True: uname="myfu" password="123" u,p=input("input your name and password:").split() count+=1 if uname ==u and password ==p: exit("login success") else: if count==3: exit("three times error input,your count is locked") else: print("error username or password ,pls try again,%s time last"%(3-count))

 

转载于:https://www.cnblogs.com/fumy/p/10248906.html