Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.
You may assume no duplicates in the array.
Here are few examples.[1,3,5,6], 5 → 2[1,3,5,6], 2 → 1[1,3,5,6], 7 → 4[1,3,5,6], 0 → 0
Hide Tags Array Binary Search Hide Similar Problems (E) First Bad Version public class Solution { public int searchInsert(int[] nums, int target) { int left = 0; int right = nums.length-1; //find the first number that is >= than target if(nums[right] < target) return right+1; while(left<right){ int mid = (left+right)/2; if(nums[mid] == target) return mid; if(nums[mid] > target) right = mid; else left = mid + 1; } return left; } }
转载于:https://www.cnblogs.com/neweracoding/p/5700654.html
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