1.使用while循环输入 1 2 3 4 5 6 8 9 10
# Author:Tony.lou i = 1 while i < 11: if i == 7: pass else: print (i) i+=12.求1-100所有的和
# Author:Tony.lou i = 0 n = 0 while i <100: tmp = i % 2 if tmp == 0: n = n - i else: n = n + i i = i + 1 print(n) print(sum(i for i in range(1,101)))
3.输出1-100内所有基数
i = 0 while i < 101: tmp = i % 2 if tmp != 0: print(i) else: pass i+=1 for i in range(1,100,2): print(i) View Code
4.求1-2+3-4+5..99所有数的和
# Author:Tony.lou i = 0 n = 0 while i <100: tmp = i % 2 if tmp == 0: n = n - i else: n = n + i i = i + 1 print(n)5.用户三次登录
count = 0 while count < 3: user = input('user:') password = input('password:') if user == 'tony' and password =='Omd': print('welcome') print('........') break else: print('error..try again') count += 1 View Code
转载于:https://www.cnblogs.com/lyj821202/p/9000545.html
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