一次AC
字符串就是：count+char
1 class Solution: 2 # @return a string 3 def countAndSay(self, n): 4 str = "1" 5 for i in range(n-1): 6 tmp = str 7 str = "" 8 c = tmp[0] 9 cnt = 1 10 for j in range(1,len(tmp)): 11 if tmp[j] == tmp[j-1]: 12 cnt += 1 13 else: 14 str += ("%d"%cnt + tmp[j-1]) 15 cnt = 1 16 str += ("%d"%cnt + tmp[len(tmp)-1]) 17 return str
转载于:https://www.cnblogs.com/CheeseZH/p/4033890.html
相关资源：数据结构—成绩单生成器