[刷题]算法竞赛入门经典(第2版) 5-11UVa12504 - Updating a Dictionary

it2022-07-05  157

题意:对比新老字典的区别:内容多了、少了还是修改了。


代码:(Accepted,0.000s)

//UVa12504 - Updating a Dictionary //#define _XieNaoban_ #include<iostream> #include<sstream> #include<string> #include<vector> #include<map> using namespace std; int T; int main() { #ifdef _XieNaoban_ freopen("in.txt", "r", stdin); #endif ios::sync_with_stdio(false); cin >> T; cin.ignore(); while (T--) { map<string, string> dic; for (int i(0);i < 2;++i) { string line, key, value; getline(cin, line); for (auto &r : line) if (r == ',' || r == ':' || r == '{' || r == '}') r = ' '; istringstream in(line); while (in >> key) { in >> value; if (i) { auto d(dic.find(key)); if (d != dic.end()) { if (d->second != value) d->second = "*";//changed else d->second = '&';//not changed } else dic[key] = "+";//increased } else dic[key] = value; } } vector<string> inc, rmv, chg; for (const auto& r : dic) switch (r.second[0]) { case '+': inc.push_back(r.first);break; case '*': chg.push_back(r.first);break; case '&': break; default: rmv.push_back(r.first);break; } if (inc.empty() && rmv.empty() && chg.empty()) cout << "No changes\n"; else { if (!inc.empty()) { cout << '+' << inc[0]; for (auto i(inc.begin() + 1);i != inc.end();++i) cout << ',' << *i; cout << '\n'; } if (!rmv.empty()) { cout << '-' << rmv[0]; for (auto i(rmv.begin() + 1);i != rmv.end();++i) cout << ',' << *i; cout << '\n'; } if (!chg.empty()) { cout << '*' << chg[0]; for (auto i(chg.begin() + 1);i != chg.end();++i) cout << ',' << *i; cout << '\n'; } } cout << '\n'; } return 0; }

分析:这题很水,轻松AC,没啥好说的。

转载于:https://www.cnblogs.com/xienaoban/p/6798083.html


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