58. Length of Last Word

原题： Given a string s consists of upper/lower-case alphabets and empty space characters ’ ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

Example:

Input: "Hello World" Output: 5

翻译： 给你一个由大小写字母和空格组成的字符串s, 返回字符串最后一个单词的长度

如果最后一个单词不存在就返回0 注意: A单词定义为仅由非空格字符组成字符序列。

例:

Input: "Hello World" Output: 5

C程序

int lengthOfLastWord(char * s){ int num = 0; int prev = 0; while(*s!='\0') { if(*s == ' ') { if(num!=0)prev = num; num = 0; } if(*s<=90 && *s>=65 || *s>=97 && *s<=122) { ++num; } ++s; } if(num==0)return prev; return num; }

总结： 本题难点是对最后为空格的字符串的处理