1086 Tree Traversals Again (25 分)

it2024-11-13  13

An inorder binary tree traversal can be implemented in a non-recursive way with a stack. For example, suppose that when a 6-node binary tree (with the keys numbered from 1 to 6) is traversed, the stack operations are: push(1); push(2); push(3); pop(); pop(); push(4); pop(); pop(); push(5); push(6); pop(); pop(). Then a unique binary tree (shown in Figure 1) can be generated from this sequence of operations. Your task is to give the postorder traversal sequence of this tree.

Figure 1

Input Specification:

Each input file contains one test case. For each case, the first line contains a positive integer N (≤30) which is the total number of nodes in a tree (and hence the nodes are numbered from 1 to N). Then 2N lines follow, each describes a stack operation in the format: "Push X" where X is the index of the node being pushed onto the stack; or "Pop" meaning to pop one node from the stack.

Output Specification:

For each test case, print the postorder traversal sequence of the corresponding tree in one line. A solution is guaranteed to exist. All the numbers must be separated by exactly one space, and there must be no extra space at the end of the line.

Sample Input:

6 Push 1 Push 2 Push 3 Pop Pop Push 4 Pop Pop Push 5 Push 6 Pop Pop

Sample Output:

3 4 2 6 5 1 #include <iostream> #include <queue> #include <stack> #include <cstring> using namespace std; struct node { int data; node* lchild; node* rchild; }; int n, num = 0; int pre[51], post[51], in[51]; node* create(int preL, int preR, int inL, int inR) { if (preL > preR) return NULL; node* root = new node; root->data = pre[preL]; int k; for (k = inL; k <= inR; k++) { if (in[k] == pre[preL]) break; } int numLeft = k - inL; root->lchild = create(preL + 1, preL + numLeft, inL, k - 1); root->rchild = create(preL + numLeft + 1, preR, k + 1, inR); return root; } void preTrave(node* root) { if (root == NULL) return ; preTrave(root->lchild); preTrave(root->rchild); printf("%d", root->data); num++; if (num < n) printf(" "); } int main() { char str[10]; stack<int> s; int prei = 0, ini = 0; scanf("%d", &n); while (scanf("%s", str) != EOF) { int temp; if (strcmp(str, "Push") == 0) { scanf("%d", &temp); pre[prei++] = temp; s.push(temp); } else if (strcmp(str, "Pop") == 0) { in[ini++] = s.top(); s.pop(); } } while (!s.empty()) { in[ini++] = s.top(); s.pop(); } node* root = create(0, n -1, 0, n - 1); preTrave(root); return 0; }

 

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