一个比较复杂的查询语句

it2024-11-19  8

 Access中不支持视图,认为视图是个复杂查询。

Create View TV as select B.IPDCode as 类别,B.Grade,count(B.Grade) as 数目 From WW_IPD A,WW_SM B Where A.IPDCode = B.IPDCode And B.Grade="建议推荐"  group by B.IPDCode,B.Gradeunionselect B.IPDCode as 类别,B.Grade,count(B.Grade) as 数目 From WW_IPD A,WW_SM B Where A.IPDCode = B.IPDCode And B.Grade="暂不推荐" group by B.IPDCode,B.Grade;

Access中不认识关键字“View”。

第一版查询语句:

select B.IPDCode as 类别,B.Grade,count(B.Grade) as 数目 From WW_IPD A,WW_SM B Where A.IPDCode = B.IPDCode And B.Grade="建议推荐"  group by B.IPDCode,B.Gradeunionselect B.IPDCode as 类别,B.Grade,count(B.Grade) as 数目 From WW_IPD A,WW_SM B Where A.IPDCode = B.IPDCode And B.Grade="暂不推荐" group by B.IPDCode,B.Grade;

第二版改进型查询语句:

 select B.IPDCode as 类别,count(B.Grade) as 建议推荐,

(select count(B.Grade) From WW_IPD C,WW_SM D Where C.IPDCode = D.IPDCode And D.Grade="暂不推荐" AND C.IPDCode=B.IPDCode )as 暂不推荐

From WW_IPD A,WW_SM B Where A.IPDCode = B.IPDCode And B.Grade="建议推荐"  group by B.IPDCode,B.Grade

 

第二版语句有漏洞,下面为第三版改进型查询语句:

 

select B.IPDCode as 类别,(select count(B.Grade) From WW_IPD C,WW_SM D Where C.IPDCode = D.IPDCode And D.Grade="暂不推荐" AND C.IPDCode=B.IPDCode )as 暂不推荐, count(B.Grade) as 建议推荐

From WW_IPD A,WW_SM B Where A.IPDCode = B.IPDCode And B.Grade="建议推荐"  group by B.IPDCode,B.Grade

unionselect B.IPDCode as 类别,count(B.Grade) as 暂不推荐,

(select count(B.Grade) From WW_IPD C,WW_SM D Where C.IPDCode = D.IPDCode And D.Grade="建议推荐" AND C.IPDCode=B.IPDCode )as 建议推荐

From WW_IPD A,WW_SM B Where A.IPDCode = B.IPDCode And B.Grade="暂不推荐"  group by B.IPDCode,B.Grade

 

*感悟:用户需求促使我们技术探索!

转载于:https://www.cnblogs.com/wuhenke/archive/2010/07/13/1776562.html

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