网上找到如下几个思路：
1、用inspect模块
2、用sys._getframe模块
3、用sys.exc_traceback，先抛一个异常，然后抓出traceback
#!/usr/bin/env python # -*- coding: utf-8 -*- import sys def test(depth = 0): frame = sys._getframe(depth) code = frame.f_code print "frame depth = ", depth print "func name = ", code.co_name print "func filename = ", code.co_filename print "func lineno = ", code.co_firstlineno print "func locals = ", frame.f_locals def main(): test(0) print "--------" test(1) if __name__ == "__main__": main()
import inspect class A: def a(self): print("A.a()") B().b() class B: def b(self): print("B.b()") stack = inspect.stack() the_class = stack[1][0].f_locals["self"].__class__ the_method = stack[1][0].f_code.co_name print(" I was called by {}.{}()".format(str(the_class), the_method)) A().a()
def currentframe(): """Return the frame object for the caller's stack frame.""" try: raise Exception except: return sys.exc_traceback.tb_frame.f_back
更多信息可参考：
http://stackoverflow.com/questions/11799290/get-function-callers-information-in-python
http://stackoverflow.com/questions/900392/getting-the-caller-function-name-inside-another-function-in-python
http://stackoverflow.com/questions/17065086/how-to-get-the-caller-class-name-inside-a-function-of-another-class-in-python
转载于:https://www.cnblogs.com/tuzkee/p/3243110.html
