冒泡算法

it2025-01-25  19

#!/bin/python

a=[1,2,3,4,5,6]#a=[6,5,4,3,2,1]flag = Falsefor i in range(0,len(a)-1):# print ("FLAG" + str(flag))   if flag :     break   flag = True   for j in range(0,len(a)-i-1):     if a[j]>a[j+1]:       tmp = a[j]       a[j] = a[j+1]       a[j+1] = tmp       flag = False    # print flag     print a

 

转载于:https://www.cnblogs.com/linlianhuan/p/10034873.html

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