买卖股票的最佳时机

it2025-04-04  20

       int ret = 0;        if(prices.size()<2)            return ret;        int lowest = prices[0];        for(int i=1;i<prices.size();i++)        {            int cur = prices[i];            ret = max(ret,cur-lowest);            lowest  = min(lowest,cur);        }        return ret;    }};

 

转载于:https://www.cnblogs.com/huxiangang/p/6522784.html

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