//值传递与引用传递的差别
#include <iostream>
#include <iomanip>
using namespace std;
void fiddle(int in1, int &in2)
{
in1 = in1 + 100;
in2 = in2 + 100;
cout << "The values are ";
cout << setw(5) << in1;
cout << setw(5) << in2 << endl;
}
int main()
{
int v1 = 7, v2 = 12;
cout << "The values are:";
cout << setw(5) << v1;
cout << setw(5) << v2 << endl;
fiddle(v1, v2);
cout << "The values are:";
cout << setw(5) << v1;
cout << setw(5) << v2 << endl;
system("pause");
return 0;
}
执行结果:
7 12
107 112
7 112
能够得出结论,假设穿引用将会改变变量最初的值,而假设传值在函数中使用后并不会改变其原来的值
转载于:https://www.cnblogs.com/bhlsheji/p/5105462.html
