Oracle Minuskeyword SQL中的MINUSkeyword SQL中有一个MINUSkeyword，它运用在两个SQL语句上，它先找出第一条SQL语句所产生的结果，然后看这些结果有没有在第二个SQL语句的结果中。假设有的话，那这一笔记录就被去除，而不会在最后的结果中出现。假设第二个SQL语句所产生的结果并没有存在于第一个SQL语句所产生的结果内，那这笔资料就被抛弃，其语法例如以下： [SQL Segment 1] MINUS [SQL Segment 2] -------------------------------------------- //创建表1 create table test1 ( name varchar(10), sex varchar(10), );
insert into test1 values('test','female'); insert into test1 values('test1','female'); insert into test1 values('test1','female'); insert into test1 values('test11','female'); insert into test1 values('test111','female');
//创建表2 create table test2 ( name varchar(10), sex varchar(10), ); insert into test1 values('test','female'); insert into test1 values('test2','female'); insert into test1 values('test2','female'); insert into test1 values('test22','female'); insert into test1 values('test222','female'); -------------------------------------------
select * from test1 minus select * from test2;
结果：
NAME SEX ---------- ---------- test1 female test11 female test111 female -----------------------------------------------------------
select * from test2 minus select * from test1;
结果:
NAME SEX ---------- ---------- test2 female test22 female test222 female
结论：Minus返回的总是左边表中的数据，它返回的是差集。注意：minus有剃重作用
========================================================== 以下是我做的实验，非常明显可以看出MINUS的效率，made_order共23万笔记录，charge_detail共17万笔记录
性能比較: SELECT order_id FROM made_order MINUS SELECT order_id FROM charge_detail 1.14 sec SELECT a.order_id FROM made_order a WHERE NOT exists ( SELECT order_id FROM charge_detail WHERE order_id = a.order_id ) 18.19 sec SELECT order_id FROM made_order WHERE order_id NOT in ( SELECT order_id FROM charge_detail ) 20.05 sec 还有其他一下keyword： INTERSECT (交集) UNION ALL 并集
转载于:https://www.cnblogs.com/bhlsheji/p/4004115.html
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