Two elements of a binary search tree (BST) are swapped by mistake.
Recover the tree without changing its structure.
Example 1:
Input: [1,3,
null,
null,2
]
1
/
3
\
2
Output: [3,1,
null,
null,2
]
3
/
1
\
2
Example 2:
Input: [3,1,4,
null,
null,2
]
3
/
\
1 4
/
2
Output: [2,1,4,
null,
null,3
]
2
/
\
1 4
/
3
Follow up:
A solution using O(n) space is pretty straight forward.Could you devise a constant space solution?
题意:
二叉搜索树中的两个节点被调换了,麻烦给调回来。
转载于:https://www.cnblogs.com/liuliu5151/p/9175890.html