int main () {
double a, c;
double x =
0, y =
100,m;
int b;
scanf("%lf%d%lf",&a,&b,&
c);
while( y - x > 1e-
5) {
printf("%f ", y);
m = x + (y-x)/
2;
double f =
a;
for (
int i =
0; i < b; i++ ) f += f*m/
100-
c;
if (f<
0) x = m;
else y =
m;
}
printf("%f\n", y);
system("PAUSE");
return 0;
}
转载于:https://www.cnblogs.com/tsubasa/archive/2012/12/12/2815511.html
相关资源:C#非线性方程组算法
转载请注明原文地址: https://win8.8miu.com/read-1553600.html