"""多个装饰器装饰一个函数，执行效果类似于俄罗斯套娃（3210123）,难点在于各种传值"""def wapper(func):#func=inner2 def inner1(*args,**kwargs): print('子丑寅卯') ret=func(*args,**kwargs) print('辰巳午未') return ret return inner1def wapper2(func):#func=inner1 def inner2(*args,**kwargs): print('申酉戌亥') ret=func(*args,**kwargs) print('完成') return ret return inner2@wapper #Nauth=wapper(inner2)=func=inner1@wapper2 #Nauth=wapper2(Nauth)=func=inner2def Nauth(): print('嵌套') return 'MOBA'print(Nauth())
转载于:https://www.cnblogs.com/sihong/p/11056948.html
相关资源：俄罗斯套娃问题 回溯法
