asp.net中使用PostBackUrl，后如何获取上一页的值

a.aspx

<asp:RadioButtonList ID="Test1" runat="server"><asp:ListItem Value="1">test</asp:ListItem><asp:ListItem Value="2">tttt</asp:ListItem></asp:RadioButtonList>      <asp:Button ID="Button1" PostBackUrl="~/JSpell.aspx" runat="server" Text="Button" /> 

b.aspx.cs

    RadioButtonList my = (RadioButtonList)this.PreviousPage.FindControl("Test1");   [1]. Response.Write(my.SelectedValue);   [2]. Response.Write(Request.Form["Test1"]); 

 

转载于:https://www.cnblogs.com/lfzwenzhu/archive/2010/05/20/1740168.html