int d[maxn];
bool bfs(){
//在残量网络上构造分层图
memset(d,
0,
sizeof d);
queue<
int>
q;
while(q.size())q.pop();
q.push(s);d[s]=
1;
while(q.size()){
int x=
q.front();q.pop();
for(
int i=head[x];i!=-
1;i=
e[i].nxt){
int y=
e[i].to;
if(d[y] || e[i].w==
0)
continue;
q.push(y);
d[y]=d[x]+
1;
if(y==t)
return 1;
}
}
return 0;
}
int dfs(
int x,
int flow){
if (x==t)
return flow;
int rest=
flow;
for(
int i=head[x];i!=-
1 && rest>
0;i=
e[i].nxt){
int y=
e[i].to;
if(e[i].w==
0 || d[y]!=d[x]+
1)
continue;
int k=
dfs(y,min(rest,e[i].w));
if(!k) d[y]=
0;
//y点已经被增广完毕,本次dinic时不会再访问这个点
e[i].w-=k; e[i^
1].w+=
k;
rest-=
k;
}
return flow-
rest;
}
int flow=
0,ans=
0;
while(bfs())
while(flow=
dinic(s,inf))
ans+=flow;
转载于:https://www.cnblogs.com/zsben991126/p/10994054.html
相关资源:性能测试进阶指南——LoadRunner11实战 part1