1.导入别的表
insert into EMPI_IDENTIFY select id,empiid, name||':' ||idcardno,'accidcardno','' from empi_main where empi_state ='正常';insert into EMPI_IDENTIFY select sys_guid(),empiid, name||':' ||tel,'acctel','' from empi_main where empi_state ='正常' and tel is not null;
2.
delete FROM empi_cross where id in( SELECT id from ( SELECT ROW_NUMBER() OVER(PARTITION BY t.linkempiid ORDER BY t.linkempiid) rn, t.* FROM empi_cross t ) WHERE rn = 2 )
转载于:https://www.cnblogs.com/leolzi/p/10902471.html
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