leetcode

it2022-05-05  108

解题思路:

这里需要注意,初始化的时候输入的nestedList里面的元素是上面的注释的定义的类别的实例。注意调用其中的方法,其余的就比较简单了。

具体代码如下:

# """ # This is the interface that allows for creating nested lists. # You should not implement it, or speculate about its implementation # """ #class NestedInteger(object): # def isInteger(self): # """ # @return True if this NestedInteger holds a single integer, rather than a nested list. # :rtype bool # """ # # def getInteger(self): # """ # @return the single integer that this NestedInteger holds, if it holds a single integer # Return None if this NestedInteger holds a nested list # :rtype int # """ # # def getList(self): # """ # @return the nested list that this NestedInteger holds, if it holds a nested list # Return None if this NestedInteger holds a single integer # :rtype List[NestedInteger] # """ class NestedIterator(object): def __init__(self, nestedList): """ Initialize your data structure here. :type nestedList: List[NestedInteger] """ self.data = [] self.get_data(nestedList, self.data) self.ptr = 0 def get_data(self, nestedList, _data): for sample in nestedList: if sample.isInteger(): _data.append(sample.getInteger()) else: self.get_data(sample.getList(), _data) def next(self): """ :rtype: int """ res = self.data[self.ptr] self.ptr += 1 return res def hasNext(self): """ :rtype: bool """ if self.ptr == len(self.data): return False return True # Your NestedIterator object will be instantiated and called as such: # i, v = NestedIterator(nestedList), [] # while i.hasNext(): v.append(i.next())

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