--
不解释。。
WITH
SimpleRecursive ( Employee_NM, Employee_ID, ReportsTo ,Sublevel)
AS
(
SELECT
Employee_NM , Employee_ID , ReportsTo,
0
FROM
Employee_Tree
WHERE
Employee_ID
=
2
UNION
ALL
SELECT
p.Employee_NM , p.Employee_ID , p.ReportsTo, Sublevel
+
1
FROM
Employee_Tree p
INNER
JOIN
SimpleRecursive A
ON
A.Employee_ID
=
p.ReportsTo )
SELECT
sr.Employee_ID
AS
empid , sr.Employee_NM
AS
Emp , et.Employee_NM
AS
Boss
FROM
SimpleRecursive sr
INNER
JOIN
Employee_Tree et
ON
sr.ReportsTo
=
et.Employee_ID
WHERE
Sublevel
<=
2
转载于:https://www.cnblogs.com/renjuwht/archive/2010/10/03/1841515.html
转载请注明原文地址: https://win8.8miu.com/read-21871.html