cte递归

it2022-05-05  146

-- 不解释。。 WITH     SimpleRecursive ( Employee_NM, Employee_ID, ReportsTo ,Sublevel)           AS  (  SELECT    Employee_NM ,                        Employee_ID ,                        ReportsTo,                         0                 FROM      Employee_Tree                WHERE     Employee_ID  =   2                 UNION   ALL                 SELECT    p.Employee_NM ,                        p.Employee_ID ,                        p.ReportsTo,                        Sublevel  +   1                 FROM      Employee_Tree p                         INNER   JOIN  SimpleRecursive A  ON  A.Employee_ID  =  p.ReportsTo             )     SELECT   sr.Employee_ID  AS  empid ,            sr.Employee_NM  AS  Emp ,            et.Employee_NM  AS  Boss           FROM     SimpleRecursive sr             INNER   JOIN  Employee_Tree et  ON  sr.ReportsTo  =  et.Employee_ID             WHERE     Sublevel  <= 2

 

转载于:https://www.cnblogs.com/renjuwht/archive/2010/10/03/1841515.html


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