url:
http://xxxx.com?name=魅力&id=123
js中:
var name = getUrlParam("name");
/*通过正则获取url中的参数*/function getUrlParam(name){ var reg = new RegExp("(^|&)"+ name +"=([^&]*)(&|$)"); var r = window.location.search.substr(1).match(reg); if(r!=null)return decodeURI(r[2]); return null;}
转载于:https://www.cnblogs.com/tangmj/p/5567058.html
相关资源:通过正则表达式获取url中参数的简单实现