单色位图格式
如果您在处理小块单色图像，那么您不必把它们当成资源来建立。与彩色位图对象不同，单色位的格式相对简单一些，而且几乎能全部从您要建立的图像中分离出来。例如，假定您要建立下图所示的位图：
您能写下一系列的位（0代表黑色，1代表白色），这些位直接对应于网格。从左到右读这些位，您能给每8字节配置一个十六进制元的字节值。如果位图的宽度不是16的倍数，在字节的右边用零填充，以得到偶数个字节：
0 1 0 1 0 0 0 1 0 1 1 1 0 1 1 1 0 0 0 1 = 51 77 10 00 0 1 0 1 0 1 1 1 0 1 1 1 0 1 1 1 0 1 0 1 = 57 77 50 00 0 0 0 1 0 0 1 1 0 1 1 1 0 1 1 1 0 1 0 1 = 13 77 50 00 0 1 0 1 0 1 1 1 0 1 1 1 0 1 1 1 0 1 0 1 = 57 77 50 00 0 1 0 1 0 0 0 1 0 0 0 1 0 0 0 1 0 0 0 1 = 51 11 10 00图素宽为20，扫描线高为5，字节宽为4。您可以用下面的叙述来设定此位图的BITMAP结构：
static BITMAP bitmap = { 0, 20, 5, 4, 1, 1 } ;并且可以将位储存在BYTE数组中：
static BYTE bits [] = { 0x51, 0x77, 0x10, 0x00, 0x57, 0x77, 0x50, 0x00, 0x13, 0x77, 0x50, 0x00, 0x57, 0x77, 0x50, 0x00, 0x51, 0x11, 0x10, 0x00 } ;用CreateBitmapIndirect来建立位图需要下面两条叙述：
bitmap.bmBits = (PSTR) bits ; hBitmap = CreateBitmapIndirect (&bitmap) ;另一种方法是：
hBitmap = CreateBitmapIndirect (&bitmap) ; SetBitmapBits (hBitmap, sizeof bits, bits) ;您也可以用一道叙述来建立位图：
hBitmap = CreateBitmap (20, 5, 1, 1, bits) ;#include "stdafx.h"LRESULT CALLBACK WndProc (HWND, UINT, WPARAM, LPARAM) ;
int APIENTRY WinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPSTR lpCmdLine, int nCmdShow){ static TCHAR szAppName [] = TEXT ("Bricks2") ; HWND hwnd; MSG msg ; WNDCLASS wndclass ; wndclass.style = CS_HREDRAW | CS_VREDRAW ; wndclass.lpfnWndProc= WndProc ; wndclass.cbClsExtra = 0 ; wndclass.cbWndExtra = 0 ; wndclass.hInstance = hInstance ; wndclass.hIcon = LoadIcon (NULL, IDI_APPLICATION) ; wndclass.hCursor = LoadCursor (NULL, IDC_ARROW) ; wndclass.hbrBackground = (HBRUSH) GetStockObject (WHITE_BRUSH) ; wndclass.lpszMenuName = NULL ; wndclass.lpszClassName = szAppName ; if (!RegisterClass (&wndclass)) {MessageBox (NULL, TEXT ("This program requires Windows NT!"),szAppName, MB_ICONERROR) ; return 0 ; } hwnd = CreateWindow (szAppName, TEXT ("CreateBitmap Demo"),WS_OVERLAPPEDWINDOW, CW_USEDEFAULT, CW_USEDEFAULT,CW_USEDEFAULT, CW_USEDEFAULT,NULL, NULL, hInstance, NULL) ; ShowWindow (hwnd, nCmdShow) ; UpdateWindow (hwnd) ; while (GetMessage (&msg, NULL, 0, 0)) {TranslateMessage (&msg) ; DispatchMessage (&msg) ; } return msg.wParam ;}LRESULT CALLBACK WndProc ( HWND hwnd, UINT message, WPARAM wParam,LPARAM lParam)
{ static BITMAP Pbitmap = { 0, 20, 5, 4, 1, 1 } ; static BYTE bits[20][5]={ 0x51, 0x77, 0x10, 0x00, 0x57, 0x77, 0x50, 0x00, 0x13, 0x77, 0x50, 0x00, 0x57, 0x77, 0x50, 0x00, 0x51, 0x11, 0x10, 0x00 } ;
// static BYTE bits [8][2]={ 0xFF,0,0x0C,0,0x0C,0,0x0C,0,0xFF,0,0xC0,0,0xC0,0,0xC0,0 } ; static HBITMAP hBitmap ; static int cxClient, cyClient, cxSource, cySource ; HDC hdc, hdcMem ; int x, y ; PAINTSTRUCT ps ; switch (message) {case WM_CREATE: Pbitmap.bmBits = bits ; hBitmap = CreateBitmapIndirect (&Pbitmap) ; cxSource = Pbitmap.bmWidth ; cySource = Pbitmap.bmHeight ; return 0 ; case WM_SIZE: cxClient = LOWORD (lParam) ; cyClient = HIWORD (lParam) ; return 0 ; case WM_PAINT: hdc = BeginPaint (hwnd, &ps) ; hdcMem = CreateCompatibleDC (hdc) ; SelectObject (hdcMem, hBitmap) ; for (y = 0 ; y < 5 ; y += cySource) for (x = 0 ; x < 20 ; x += cxSource) {BitBlt (hdc, x, y, 200, 50, hdcMem, 0, 0, SRCCOPY) ;} StretchBlt (hdc, 0, 0, cxClient, cyClient,hdcMem, 0, 0, cxSource, cySource, MERGECOPY); DeleteDC (hdcMem) ; EndPaint (hwnd, &ps) ; return 0 ; case WM_DESTROY: DeleteObject (hBitmap) ; PostQuitMessage (0) ; return 0 ; } return DefWindowProc (hwnd, message, wParam, lParam) ; }
转载于:https://www.cnblogs.com/kay_leo/archive/2010/09/13/1824979.html
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