给定一个01矩阵，对矩阵进行一下操作：
水平方向翻转图像，如：[1,1,0]水平翻转之后变为[0,1,1]
倒置图像的每个元素，即用0替代1，用1替代0。如：[0,1,1]变为[1,0,0]
测试样例：
输入：[ [1,1,0],[1,0,1],[0,0,0] ]
输出：[ [1,0,0],[0,1,0],[1,1,1] ]
代码实现：
1.C++实现
#pragma once#include<vector>using namespace std;class FlipAndInverImageClass{public: vector<vector<int>> flipAndInvertImage(vector<vector<int>>& A) { vector<vector<int>> result; vector<int> mid; for (int i = 0; i < A.size(); ++i) { for (int j = A[i].size() - 1; j >= 0; --j) { //通过与1异或得到取反，让j从末尾开始实现矩阵行的翻转 mid.push_back( A[i][j] ^ 1 ); } result.push_back( mid ); mid.clear(); } return result; }};2.Java实现
public class HelloWorld {public static void main(String[] args){int[][] array = new int[][]{{1,1,0},{1,0,1},{0,0,0}}; SolutionClass solutionClass = new SolutionClass(); int[][] result = solutionClass.flipAndInverImage(array); for(int i=0;i<result.length;++i){for(int j=0;j<result[i].length;++j){ System.out.print(result[i][j]+" "); } System.out.println(); } }}class SolutionClass{public int[][] flipAndInverImage(int[][] A) {for (int[] rows : A) {int start = 0, end = rows.length-1; while (start <= end) {int temp = rows[start]^1; rows[start] = rows[end]^1; rows[end] = temp; start++; end--; } }return A; }}
转载于:https://www.cnblogs.com/Tomorrow-will-be-better/p/11123680.html
