1 //char 0-255一共256个
2 char getonebyhash(
char *
str)
3 {
4 if (str ==
NULL)
5 {
6 return '\0';
7 }
8 char ch =
'\0';
9 //哈希表设置为0
10 int hashtable[
256] = {
0 };
11 //依次获取
12 char *phash =
str;
13
14 //遍历循环字符串数据存放在hash表
15 while (*phash !=
'\0')
16 {
17 hashtable[*phash]++
;
18 phash++
;
19 }
20
21 //备份首地址，寻找到第一个值为1的字符
22 phash =
str;
23 while (*phash !=
'\0')
24 {
25 if (hashtable[*phash] ==
1)
26 {
27 ch = *
phash;
28 break;
29 }
30 phash++
;
31 }
32 return ch;
33
34
35 }
转载于:https://www.cnblogs.com/xiaochi/p/8366143.html
