python加解密

it2022-05-05  229

python加解密 from Crypto.Cipher import AES import base64 secret_key = '1234567890123456' # 密匙 msg_text = 'test some plain text here'.rjust(32) cipher = AES.new(secret_key, AES.MODE_ECB) encoded = base64.b64encode(cipher.encrypt(msg_text)) decoded = cipher.decrypt(base64.b64decode(encoded)) print(decoded.strip()) 加密算法 ======================== ======= ======================== Module name Type Description ======================== ======= ======================== `Crypto.Cipher.AES` Block Advanced Encryption Standard `Crypto.Cipher.ARC2` Block Alleged RC2 `Crypto.Cipher.ARC4` Stream Alleged RC4 `Crypto.Cipher.Blowfish` Block Blowfish `Crypto.Cipher.CAST` Block CAST `Crypto.Cipher.DES` Block The Data Encryption Standard.Very commonly used in the past, but today its 56-bit keys are too small. `Crypto.Cipher.DES3` Block Triple DES. `Crypto.Cipher.XOR` Stream The simple XOR cipher. ======================== ======= ======================== | - For `MODE_ECB`, `MODE_CBC`, and `MODE_OFB`, *ciphertext* length | (in bytes) must be a multiple of *block_size*. | | - For `MODE_CFB`, *ciphertext* length (in bytes) must be a multiple | of *segment_size*/8. | | - For `MODE_CTR`, *ciphertext* can be of any length. | | - For `MODE_OPENPGP`, *plaintext* must be a multiple of *block_size*, | unless it is the last chunk of the message. posted on 2018-03-23 16:40 北京涛子 阅读( ...) 评论( ...) 编辑 收藏

转载于:https://www.cnblogs.com/liujitao79/p/8631140.html


最新回复(0)