破解vba工程密码——VBA代码

it2022-05-05  158

新建一个模块,然后复制以下代码,如果出现“文件解密成功”,则表明解密成功

Public Sub VBAPassword() Filename = Application.GetOpenFilename("Excel文件(*.xls & *.xla & *.xlt),*.xls;*.xla;*.xlt", , "VBA破解") If Dir(Filename) = "" Then MsgBox "没找到相关文件,清重新设置。" End Else FileCopy Filename, Filename & ".bak" '备份文件。 End If Dim GetData As String * 5 Open Filename For Binary As #1 Dim CMGs As Long Dim DPBo As Long For i = 1 To LOF(1) Get #1, i, GetData If GetData = "CMG=""" Then CMGs = i If GetData = "[Host" Then DPBo = i - 2: Exit For Next If CMGs = 0 Then MsgBox "请先对VBA编码设置一个保护密码...", 32, "提示" Exit Sub End If Dim St As String * 2 Dim s20 As String * 1 '取得一个0D0A十六进制字串 Get #1, CMGs - 2, St '取得一个20十六制字串 Get #1, DPBo + 16, s20 '替换加密部份机码 For i = CMGs To DPBo Step 2 Put #1, i, St Next '加入不配对符号 If (DPBo - CMGs) Mod 2 <> 0 Then Put #1, DPBo + 1, s20 End If MsgBox "文件解密成功......", 32, "提示" Close #1 End Sub

 


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