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We are given a list of (axis-aligned) rectangles. Each rectangle[i] = [x1, y1, x2, y2] , where (x1, y1) are the coordinates of the bottom-left corner, and (x2, y2) are the coordinates of the top-right corner of the ith rectangle.
Find the total area covered by all rectanglesin the plane. Since the answer may be too large, return it modulo 10^9 + 7.
Example 1:
Input: [[0,0,2,2],[1,0,2,3],[1,0,3,1]] Output: 6 Explanation: As illustrated in the picture.Example 2:
Input: [[0,0,1000000000,1000000000]] Output: 49 Explanation: The answer is 10^18 modulo (10^9 + 7), which is (10^9)^2 = (-7)^2 = 49.Note:
1 <= rectangles.length <= 200rectanges[i].length = 40 <= rectangles[i][j] <= 10^9The total area covered by all rectangles will never exceed 2^63 - 1 and thus will fit in a 64-bit signed integer.我们给出了一个(轴对齐的)矩形列表 rectangles 。 对于 rectangle[i] = [x1, y1, x2, y2],其中(x1,y1)是矩形 i 左下角的坐标,(x2,y2)是该矩形右上角的坐标。
找出平面中所有矩形叠加覆盖后的总面积。 由于答案可能太大,请返回它对 10 ^ 9 + 7 取模的结果。
示例 1:
输入:[[0,0,2,2],[1,0,2,3],[1,0,3,1]] 输出:6 解释:如图所示。示例 2:
输入:[[0,0,1000000000,1000000000]] 输出:49 解释:答案是 10^18 对 (10^9 + 7) 取模的结果, 即 (10^9)^2 → (-7)^2 = 49 。提示:
1 <= rectangles.length <= 200rectanges[i].length = 40 <= rectangles[i][j] <= 10^9矩形叠加覆盖后的总面积不会超越 2^63 - 1 ,这意味着可以用一个 64 位有符号整数来保存面积结果。
转载于:https://www.cnblogs.com/strengthen/p/10593383.html