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Implement function ToLowerCase() that has a string parameter str, and returns the same string in lowercase.
Example 1:
Input: "Hello" Output: "hello"Example 2:
Input: "here" Output: "here"Example 3:
Input: "LOVELY" Output: "lovely"实现函数 ToLowerCase(),该函数接收一个字符串参数 str,并将该字符串中的大写字母转换成小写字母,之后返回新的字符串。
示例 1:
输入: "Hello" 输出: "hello"示例 2:
输入: "here" 输出: "here"示例 3:
输入: "LOVELY" 输出: "lovely"4ms
1 class Solution { 2 func ord(ch: String) -> Int? { 3 for st in ch.utf16 { 4 return Int(st) 5 } 6 return nil 7 } 8 9 func ord(val: UInt16) -> Character? { 10 if let us = UnicodeScalar(val){ 11 return Character(us) 12 } 13 return nil 14 } 15 16 func toLowerCase(_ str: String) -> String { 17 guard str.count > 0 else { 18 return "" 19 } 20 var s = Array(str) 21 for ch in s.enumerated() { 22 if var ordVal = ord(ch: String(ch.element)), ordVal >= 65 && ordVal <= 90 { 23 ordVal = ordVal + 32 24 if let modVal = ord(val: UInt16(ordVal)) { 25 s[ch.offset] = modVal 26 } 27 } 28 } 29 return String(s) 30 } 31 }19040kb
1 class Solution { 2 3 func toLowerCase(_ str: String) -> String { 4 var word = String() 5 for i in str.utf8{ 6 var i = i 7 if i >= 65 && i <= 90 { 8 word.append(Character(UnicodeScalar(i + 32))) 9 } 10 else { 11 word.append(Character(UnicodeScalar(i))) 12 } 13 } 14 return word 15 } 16 }19112kb
1 class Solution { 2 func toLowerCase(_ str: String) -> String { 3 return String(str.utf8.map({ (ascii) -> Character in 4 var charCode = Int(ascii) 5 if 65 <= charCode && charCode <= 90 { 6 charCode += 32 7 } 8 return Character(UnicodeScalar(charCode)!) 9 })) 10 } 11 }
转载于:https://www.cnblogs.com/strengthen/p/10506475.html
相关资源:数据结构—成绩单生成器