1050 String Subtraction (20 分)

1050 String Subtraction (20 分)  

Given two strings S​1​​ and S​2​​, S=S​1​​−S​2​​ is defined to be the remaining string after taking all the characters in S​2​​ from S​1​​. Your task is simply to calculate S​1​​−S​2​​ for any given strings. However, it might not be that simple to do it fast.

Input Specification:

Each input file contains one test case. Each case consists of two lines which gives S​1​​ and S​2​​, respectively. The string lengths of both strings are no more than 1. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

Output Specification:

For each test case, print S​1​​−S​2​​ in one line.

Sample Input:

They are students. aeiou

Sample Output:

Thy r stdnts.送分题就不多说了。 1 #include <bits/stdc++.h> 2 3 using namespace std; 4 string s, ss; 5 int vis[500]; 6 int main(){ 7 getline(cin, s); 8 getline(cin, ss); 9 for(int i = 0; i < ss.length(); i++) 10 vis[ss[i]] = 1; 11 for(int i = 0; i < s.length(); i++) 12 if(!vis[s[i]]){ 13 cout <<s[i]; 14 } 15 cout << endl; 16 17 return 0; 18 }

 

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