PAT乙级1038 统计同成绩学生 (20 分)

it2022-05-05  170

https://pintia.cn/problem-sets/994805260223102976/problems/994805284092887040

用cin cout容易超时

#include <iostream> using namespace std; int score[101] = {0}, n, tmp, k; int main(){ cin >> n; for(int i = 0; i < n; i++){ scanf("%d", &tmp); score[tmp]++; } cin >> k >> tmp; cout << score[tmp]; for(int i = 1; i < k; i++){ cin >> tmp; cout << " " << score[tmp]; } return 0; }

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