<script src="Script/jquery-1.4.min.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(
function() {
$(
"tr").click(
function(event) {
var row = jQuery(
this)
var firstParam = row.children(
"td:eq(0)").text();
var secondParam = row.children(
"td:eq(1)").text();
var navUrl =
"CustomerDetails.aspx?cid=" + firstParam +
"&cname=" + secondParam;
top.location = navUrl;
});
});
</script>
转载于:https://www.cnblogs.com/Look_Sun/archive/2010/03/10/1682357.html
相关资源:jQuery使用Layer弹出层插件闪退问题