直接用HTTP返回JSON到浏览器

it2022-05-07  3

spring mvc 配置返回json需要两个重要的bean 

ContentNegotiatingViewResolver MappingJackson2JsonView具体看代码 <bean id="contentNegotiationManager" class="org.springframework.web.accept.ContentNegotiationManagerFactoryBean"> <property name="mediaTypes"> <value> html=text/html json=application/json xml=application/xml </value> </property> <property name="defaultContentType" value="text/html"/> </bean> <!-- ContentNegotiatingViewResolver视图解析器,利用他就可以配置多种返回值 --> <bean class="org.springframework.web.servlet.view.ContentNegotiatingViewResolver"> <property name="order" value="0"/> <property name="contentNegotiationManager" ref="contentNegotiationManager"/> <property name="viewResolvers"> <list> <bean class="org.springframework.web.servlet.view.InternalResourceViewResolver"> <property name="viewClass" value="org.springframework.web.servlet.view.JstlView"/> <property name="prefix" value="/WEB-INF/jsp/"/> <property name="suffix" value=".jsp"/> </bean> </list> </property> <property name="defaultViews"> <list> <bean class="org.springframework.web.servlet.view.json.MappingJackson2JsonView"> <property name="extractValueFromSingleKeyModel" value="true" /> </bean> <bean class="org.springframework.web.servlet.view.xml.MarshallingView"> <property name="marshaller"> <bean class="org.springframework.oxm.xstream.XStreamMarshaller" /> </property> </bean> </list> </property> </bean> <bean id="multipartResolver" class="org.springframework.web.multipart.support.StandardServletMultipartResolver"/>

 

 

转载于:https://www.cnblogs.com/BBchao/p/8528964.html


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